Question

Angle is isosceles with AB = AC = 7.5 cm and BC = 9cm . The height AD from A to BC , is 6cm . Find the area of Angle ABC what will be the height from C to AB , which is CE ?

Answer 1

base = 6cm
height = 9cm
$area = 1 \div 2 \times base \times height$
area = 27cm2

Answer 2

Answer:

PLEASE MARK ME AS BRAINLIEST..

Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM