angle of elevation of a point 100 mts from the foot of the tree is 60°.find height of the tree
Answers
Answered by
9
Heya !!
Let AB be the three .
BC = 100 m
Angle ACB = 60°
Tan60° = AB/BC
✓3 = AB/100
AB = 100✓3 m.
Hence,
Height of tree ( AB ) = 100✓3 m.
Let AB be the three .
BC = 100 m
Angle ACB = 60°
Tan60° = AB/BC
✓3 = AB/100
AB = 100✓3 m.
Hence,
Height of tree ( AB ) = 100✓3 m.
Attachments:
Similar questions