Angle of elevation of building A from foot of the 10th floor of the building B is 60° and the angle of elevation from the foot of the building B to the 5th floor of the building A is 45°. The distance between two buildings is 25√3m. Find the height if the 10th floor of building B
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Given height of tower CD=50m
Let the height of the building, AB=h
In right angled △BDC,
⇒ tan60
o
=
BD
CD
⇒
3
=
BD
50
⇒ BD=
3
50
m
In right angled △ABD,
⇒ tan30
o
=
BD
AB
⇒
3
1
=
3
50
h
∴
3
1
=
50
3
h
∴ h=
3
50
=16.66m
∴ The height of the building is 16.66m.
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