Math, asked by harshvi19, 1 year ago

Angle of elevation of the top of a tower from a point on the ground which is 'a' metre away from the foot of the tower is 45 degree. What is the height of the tower?


harshu1311: mugha to kch smgh hi nii aa rha

Answers

Answered by swashri27
2

Its a meters

tan45 = height of tower/ base of tower

1 = h/a

h= a

Answered by wafiyanesreen
2

Answer:

Step-by-step explanation:

In triangle ABC right angled at B.

C is the point from ground and from that point angle of elevation is 45degree.

As angle C is 45 degree and angle B is 90degree then angle A will be 45 degree.

Taking CB as distance on ground from foot of the tower as a and AB be the height of the tower as h then a= h [this is because by taking AB as base then the base angles are equal so it is an isocellus triangle.So AB = BC i.e. [a=h]

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