Physics, asked by Sana3617, 1 year ago

Angle of repose of a rough inclined plane is 60 degree what is the coefficient of friction

Answers

Answered by rishiksingh2004
20

from the figure,

if theta = 60 ,

tan theta = tan60 = Ul = √3

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Answered by muscardinus
5

Given that,

Angle of repose of a rough inclined plane is 60 degree.

To find,

The coefficient of friction.

Solution,

In this case,

mg\sin \theta=\mu mg\cos\theta\\\\\mu=tan\theta\\\\\mu=tan(60)\\\\\mu=1.73

So, the coefficient of friction is 1.73.

Learn more,

Friction

https://brainly.in/question/12062264

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