Question

Angle that of vector A=2i+3j makes with y-axis is

Answer 1

A = 2i + 3j

Let angle formed by vector A with y-axis = Ф

Therefore ,

cos Ф = ( 2i + 3j )( 0 + j ) /√( 2² + 3² )

cos Ф = 3/√13

Hence , Ф = cos^-1 ( 3/√13 )