Question

AngleP and angleQ are complementary angles. If angleP =3x+15•and angleQ =x+7•,then find angleP and angleQ​

Answer 1

Answer:

Given:

angleP = 3x + 15°

angleQ = x + 7°

According to the question,

angleP and angleP are complementary angles, thus their sum must be equal to 90°.

Thus, we have;

=> angleP + angleQ = 90°

=> 3x + 15° + x + 7° = 90°

=> 4x + 22° = 90°

=> 4x = 90° - 22°

=> 4x = 68°

=> x = 68°/4

=> x = 17°

Thus,

angleP = 3x + 15°

= 3(17°) + 15°

= 51° + 15°

= 66°

angleQ = x + 7°

= 17° + 7°

= 24°

Hence, the values of angleP and angleQ are 66° and 24° respectively.

Answer 2

If P and Q are complementary angles, so their sum will be 90°

Adding P and Q, we get

(3x+15)+ (x+7)= 90°

4x+22°=90°

4x=68° (by transposing 22° on RHS)

x= 68°÷4

x=17

P=3*17+15= 66

Q=17+7= 24