Question

angles of a quadrilateral are(4x)° , 5(x+2)° , (7x - 20 )° and 6(x + 3)°​

Answer 1

Step-by-step explanation:

(4x)° + 5(x+2)° + (7x - 20 )° +6(x + 3)° = 360°

4x° + 5x° + 10° + 7x° - 20° + 6x° + 18° = 360°

9x° + 28° - 20° + 7x° + 6x° = 360°

9x° + 13x° + 8° = 360°

22x° = 360° - 8°

22x° = 352

x° = 352°

22

x° = 16°

Therefore, 1st angle = (4x)° = 4 × 16 = 64°

2nd angle = 5(x + 2)° = 5(16 + 2)° = 5(18)° = 90°

3rd angle = (7x - 20)° = (7(16) - 20)° = (112 - 20)° = 92°

4th angle = 6(x + 3)° = 6(16 + 3)° = 6(19)° = 114°

Hope it helps you....

Answer 2

Angles of a quadrilateral form 360° ( Theorem)

Therefore 4x° + 5x + 10° + 7x -20 + 6x+ 18 = 360°

22x° + 8° = 360°

22x =360 °- 8

22x = 352

x = 352 ÷22

× = 16.