angles of a triangle are equal and the third angle is greater than each one of them by 18 degree find the angles
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The sum of all angels in any triangle is always 180. now that we know that, we subtract 18 two times because the third angle is greater than the other two by 18. 180 - 18 - 18 = 144
And we know that the other two angels are equal so each one is 144/2 = 72.
Hope that helps
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Let two angels be x, x
And third be x+18
Sum of all angles of triangle =180 degree
x+x+x+18=180 degree
3x+18=180
3x=180-18degree
3x=162degree
X=162/3
X=54degree
Two angles =54degree
And third angle =x+18degree
54+18degree
=72degree
Hence third angle is 72degree
And third be x+18
Sum of all angles of triangle =180 degree
x+x+x+18=180 degree
3x+18=180
3x=180-18degree
3x=162degree
X=162/3
X=54degree
Two angles =54degree
And third angle =x+18degree
54+18degree
=72degree
Hence third angle is 72degree
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