angles of a triangle are in AP smallest angle is half of the greatest angle find angles
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As they are in AP they have a common difference
given,
smallest angle=half ×largest angle .
consider the smallest angles as x
so largest angle is 2x.
smallest. next. largest
x 2x
because there are 2 differences and it is an AP
the common difference will be x÷2
so 2nd angle = x+x÷2=3x÷2
As per ngle sum property
x+3x÷2+2x=180(degree)
9x÷2=180
x=40(degree)
3x÷2=60(degree)
2x=80(degree)
given,
smallest angle=half ×largest angle .
consider the smallest angles as x
so largest angle is 2x.
smallest. next. largest
x 2x
because there are 2 differences and it is an AP
the common difference will be x÷2
so 2nd angle = x+x÷2=3x÷2
As per ngle sum property
x+3x÷2+2x=180(degree)
9x÷2=180
x=40(degree)
3x÷2=60(degree)
2x=80(degree)
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