Question

angles of a triangle are in the ratio is 1:2:3 . Find the meausers of each angle of the triangle ?
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Answer 1

Answer:

1st angle = 30°

2nd angle = 60°

3rd angle = 90°

Step-by-step explanation:

Let the angles of the triangle be x, 2x and 3x respectively.

Then, A/q

x+2x+3x = 180° [sum of all angles of a triangle is 180°]

6x = 180°

x = $\frac{180°}{6}$

x = 30°

Hence, 1st angle = x = 30°

2nd angle = 2x = (30°×2) = 60°

3rd angle = 3x = (30°×3) = 90°

Answer 2

Step-by-step explanation:

let the angles be x, 2x & 3x.

A/q

x+2x+3x = 180° [angle sum prop of ∆]

⇒6x = 180°

⇒x = $\frac{180°}{6}$

⇒x = 30°

So, 1st angle = 30°

2nd angle = 2×30 = 60°

3rd angle = 3×30 = 90°