Question

Angles of a triangle are x degree , (x +10) degree and (x+20 ) . find the degree measures of the angles of a triangle.

Answer 1

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$<b><i>By angle sum property of the triangle$

Angle A+B+C=180

x+x+10+x+20=180

3x+30=180

3x=180-30

3x=150

x=$\frac{150}{3}$

x=50

So angle A=50 degree

Angle B=50+10

= 60 degree

Angle C=50+20

= 70 degree

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Answer 2

Here is your solution

Given:-

Angle of △  are x° , (x+10)°, (x+20)°

We know that

Sum of angle of triangle is 180°

x° + (x+10)°+ (x+20)° = 180°

x+x+10+x+20 = 180°

3x+30=180°

3x=180-30

3x=150

x = 50

Hence

angle of triangle are :-

x° =50°

(x+10)° = 50+10=60°

(x+20)°=50+20=70°

hope it helps you