Question

angles of
parallelogram
The opposite
are (3x - 2) and (x + 48) find the
measure of each angle of the
parrallelogram?​

Answer 1

ANSWER US BELOW

Step-by-step explanation:

Let four angles of given parallelogram taken in order be ∠A,∠B,∠Cand∠D respectively

Here opposite angles given ∠A=(3x−2)and∠C=(x+48)

We know that opposite angles of a parallelogram are equal

∴3x−2=x+48

2x=50

x=25

∴3x−2=73°

∠A=∠C=73°

Also we know that sum of two adjacent angles of a parallelogram is 180

∴∠A+∠B=180°

73°+∠B=180°

∠B=107°=∠D (Opposite angles are equal)

∴ All four angles of given parallelogram are 73°,107°,73°,107°

Answer 2

Let four angles of given parallelogram taken in order be ∠A,∠B,∠Cand∠D respectively

Here opposite angles given ∠A=(3x−2)and∠C=(x+48)

We know that opposite angles of a parallelogram are equal

∴3x−2=x+48

2x=50

x=25

∴3x−2=73°

∠A=∠C=73°

Also we know that sum of two adjacent angles of a parallelogram is 180

∴∠A+∠B=180°

73°+∠B=180°

∠B=107°=∠D (Opposite angles are equal)

∴ All four angles of given parallelogram are 73°,107°,73°,107°