Question

Angles Q and R of a Δ PQR are 25° and 65° which of the following is true.

PQ²+QR²=RP²

PQ²+RP²=QR²

RP²+QR²=PQ²

Answer 1

In ΔPQR,
                Q = 25 , R =65
we know that, 
      P+Q+R =180
or,  P+25+65=180
 or, p = 180-90
or,  P = 90
therefore, in ΔPQR,
                         hypotaneus = QR
                         perpendicular =RP
                          base = PQ
Now, from Pythagourous theorem, 
               $\\ PQ^{2} + RP^{2} = QR^{2}$