Question

anglesACD is an exterior angle
of trianglesABC.
anglesB = 40°, AnglesA = 70°.
Find the measure of anglesACD.
​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

We are given m∠B=40

o

m∠A=70

o

Now,

BD

is a straight ray

so, m∠ACB+m∠ACD=180

o

→(1)

In △ABC,m∠A+m∠B+m∠ACB=180

o

→(2)

From (1) & (2)

m∠A+m∠B=m∠ACD

so, m∠ACD=40

o

+70

o

m∠ACD=110

o