angular momentum in 2nd bohr orbit of H atom is x .find out angular momentum in 1st excited stage of Li 2+ion
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Answered by
102
The angular momentum of both systems is same. The angular momentum can be calculated by the help of different factors like Planck's constant and number of orbit. The product of n and h can be divided by 2 x 3.14. Lithium is present in its 2nd excited state. In case of hydrogen, the angular momentum of 2nd orbit is calculated. The solution of this is given below:
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Vaisnavee:
It's not 2nd excited state... Its 1st excited state ,so n=1
Answered by
52
Answer:
X
Explanation:
Angular momentum of 2nd Bohr orbit is x.
So, L = nh/2π = 2h/2π = h/π
For, Li2+, it is 2st excited state. This also means that n = 2.
As angular momentum does not depend on atomic number,
So, L = nh/2π = 2h/2π = h/π
Thus angular momentum of both the systems are same, i.e. x
The answer is x.
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