find the area of minor segment of a circle of radius 6 cm when it's chord subtends an angle of 60° at its centre. (√3= 1.73)
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area of minor segment = πr^2θ/360 -1/2 r^2 sinθ
=22/7*6*6*60/360 - 1/2 *6*6*sin60°
=132/7 -9√3
putting the value of √3=1.73
answer is 24.01 cm square
=22/7*6*6*60/360 - 1/2 *6*6*sin60°
=132/7 -9√3
putting the value of √3=1.73
answer is 24.01 cm square
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