Question

Angular momentum of electron 5th orbit of hydrogen atom is

Answer 1

angular momentum(L)=mvr

L=m×(v/n)×r×n^2

L=

$9 \times {10}^{ - 31} \times 2.18 \times {10}^{ - 8} \times 0.529 \times 5$

L=51.89×10^-39 kgm^2s^-2.

hope the answer is useful .