anil obtained 375 marks out of 500 in an exmation whil Sunil obtained 420 out of 600 whose performance is better
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1
Answer:
% of first exam - 375 / 500 * 100 = 75 %
and % of second exam = 420 / 600 *100 = 70%
∴I can say that the performance of first exam is better than second exam
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Given - Obtained and total marks of Anil and Sunil.
Find - Better performance.
Solution - To find the best performance, we can find the percentage of Anil and Sunil.
Performance of Anil = Marks obtained/Total marks*100
Performance of Anil = 375/500*100
Performance of Anil = 75%
Performance of Sunil = 420/600*100
Performance of Sunil = 70%
Since percentage of Anil is more than Sunil, thus, his performance is better. Thus, performance of Anil is better.
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