Math, asked by sneha120820, 4 days ago

anil obtained 375 marks out of 500 in an exmation whil Sunil obtained 420 out of 600 whose performance is better​

Answers

Answered by βαbγGυrl
1

Answer:

% of first exam - 375 / 500 * 100 = 75 %

and % of second exam = 420 / 600 *100 = 70%

∴I can say that the performance of first exam is better than second exam

Answered by Anonymous
2

Given - Obtained and total marks of Anil and Sunil.

Find - Better performance.

Solution - To find the best performance, we can find the percentage of Anil and Sunil.

Performance of Anil = Marks obtained/Total marks*100

Performance of Anil = 375/500*100

Performance of Anil = 75%

Performance of Sunil = 420/600*100

Performance of Sunil = 70%

Since percentage of Anil is more than Sunil, thus, his performance is better. Thus, performance of Anil is better.

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