Question

Anil, Sanju and Jacob are doing their maths assignment together. Anil is doing the nth question. Sanju
is 2 questions ahead of Anil but 5 questions behind Jacob. The total number of questions is 7 more than the number of questions anil is attempting.​

Answer 1

Answer:

let the question attempted by anil be x

Anil = x

Sanju = x+5

Jacob = x+5+2 = x+7

total questions = 7 + questions attempted by anil = x+7

so, Jacob is attempting all the questions of the total questions , Sanju is attempting 5 less than total questions and Anil is attempting 7 less than the total questions present.

thanks !

Answer 2

The given question is Anil, Sanju and Jacob are doing their maths assignment together. Anil is doing the nth question. Sanju is 2 questions ahead of Anil but 5 questions behind Jacob. The total number of questions is 7 more than the number of questions anil is attempting.

The no.of questions attempted by the anil is x.

He was attempting the nth question.

let the no of questions attended by each one be

anil = x

Sanju = x+2

Jacob = x+5+2=x+7.

The total question is given as 7+ no of questions anil has attempted.

which is 7+x.

It is found that Jacob had attended all the questions.

Sanju attended 5 questions less than the total.

Anil attended 7 questions less than the total questions present

#spj2

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