Chemistry, asked by rkraviii333, 1 year ago

aniline is less basic than methylamine why

Answers

Answered by cuteritu173
6
ANILINE IS LESS BASIC DUE TO LESSER AVAILABILITY OF LONE PAIR OF ELECTRONS AND ALSO DUE TO RESONANCE EFFECT WHICH DELOCALISES THE LONE PAIR ALL OVER THE BENZENE RING.

Answered by MajorLazer017
0

\huge\textcolor{orange}{\texttt{Answer :-}}

The strength of a base or an alkaline solution is determined by the pK_b value. The lower the pKb value, the stronger the base. In the case of methylamine and aniline, aniline has more pK_b value. Hence, aniline is less basic than methylamine. This happens because :

In aniline, the lone pair of electrons on N atom is delocalized over the benzene ring. As a result, electron density on the nitrogen decreases.

On the other hand, in CH_3NH_2, + I effect of CH_3 group increases the electron density on N atom.

Therefore, aniline is less basic than methylamine and hence pK_b of aniline is higher than that of methylamine and aniline is less basic than methylamine.

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