Question

Anita randomly picks 4 cards from a deck of 52-cards and places them back into the deck ( any set of 4 cards is equally likely ). Then, babita randomly chooses 8 cards out of the same deck ( any set of 8 cards is equally likely). Assume that the choice of 4 cards by anita and the choice of 8 cards by babita are independent. What is the probability that all 4 cards chosen by anita are in the set of 8 cards chosen by babita?

Answer 1

Answer:

p(A)=n(A)/n(S)

=12/52

=3/13

Step-by-step explanation:

hope it help you

Answer 2

Answer:

52C4 x 48C4

Step-by-step explanation:

Let, cards picked by Anita be 52C4

(As Anita selected 4 random cards from the pack of 52)

Now, the condition is Babita also selects 8 cards, but of her cards are the ones that Anita selected,

So,

From the total 8 cards selected by Babita, only 4 cards are new cards and other 4 are the cards selected by Anita.

Therefore,

Cards selected by Babita are 48C4

(From pack of 52, 4 are already selected by Anita So just 48 cards left.)

(From 8 selected cards by Babita, 4cards resembles Anita)

So, total number of possible ways are 52C4 x 48C4

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