Math, asked by abhi1882, 1 year ago

Ankita is four times as old as her sister after 16 years she will be only twice as old as her sister find their parents ages

Answers

Answered by Panzer786
15
Let present age of ankita's sister be X year's.


Present age of ankita = 4x year's.



After 16 years age of Ankita = ( 4x + 16 ) year's.


After 16 years age of ankita's sister = ( x + 16 ) year's.


According to the question,



4x + 16 = 2 ( x + 16 )


4x + 16 = 2x + 32


4x - 2x = 32 - 16


2x = 16


x = 8 year's.


Present age of Ankita = 4x = 4 × 8 = 32 year's.


Present age of ankita's sister = x = 8 year's.

Muskan517: Yeah
Answered by Anonymous
2
let present age of her sister is Y years.


present age of ankita is equal to 4y years.



According to the given information,


2 ( y + 16 ) = 4y + 16


2y + 32 = 4y + 16

2y = 16

y = 8 years.

present age of her sister is 8 years.

and , present age of Ankita is 32 years.
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