Question

ankur brought 2 motor bikes for ₹ 30000 each.he sold 1 at a profit of 10% and other at a loss of 10% find his total loss or gain​

Answer 1

Answer:

For the first bike, its Cost Price (CP) = Rs 3000.

Given, he sells it at a profit of 10%.

So, selling price = (100+10)% of CP

= 110% of Rs 3000

= Rs 3300

For the second bike, its Cost Price (CP) = Rs 3000.

Given, he sells it at a loss of 10%.

So, selling price = (100-10)% of CP

= 90% of Rs 3000

= Rs 2700

Total CP of the transaction = Rs (3000+3000) = Rs 6000.

Total SP of the transaction = Rs (3300+2700) = Rs 6000.

Since, CP = SP, there is neither profit nor loss in the entire transaction.

Step-by-step explanation:

Answer 2

Answer:

C.P of first motor bike= ₹30000

Profit% =10%

Profit=

$\frac{10}{100} \times 30000$

=Rs.3000

S.P= ₹33000

For second motor bike:-

C.P= ₹30000

Loss% = 10%

Loss=

$\frac{10}{100} \times 30000$

=Rs.3000

S.P=30000-3000

=₹27000

Actual C.P= 30000+30000

=₹60000

Actual S.P= 33000+27000

= ₹60000

no gain no loss