Math, asked by sasukeuchiha1397, 3 months ago

Annabelle and Navene are multiplying (4^27^5)(4^37^2).

Annabelle's Work:

(4^27^5)(4^37^2) = 4^2 + ^37^5 + ^2 = 4^57^7


Navene's Work:

(4^27^5)(4^37^2) = 4^2⋅^37^5⋅^2 = 4^67^10


Is either of them correct? Explain your reasoning. (Say Who and Why Please) (Will Give Brainliest)

Answers

Answered by user0888
34

Correct question.

Annabelle and Navene are multiplying 4^{2}\cdot7^{5} and 4^{3}\cdot 7^{2}.

Annabelle's Work:

(4^{2}\cdot7^{5})\cdot (4^{3}\cdot 7^{2})=4^{2+3}\cdot 7^{5+2}=4^5\cdot 7^7

Navene's Work:

(4^{2}\cdot7^{5})\cdot (4^{3}\cdot 7^{2})=4^{2\cdot3}\cdot 7^{5\cdot2}=4^6\cdot 7^{10}

Reasoning.

\rightarrow a^m\times a^n=(a\times a\times...\times a)\times (a\times a\times...\times a)

Here, the first bracket contains 'm' a's and the other contains 'n'

How many a's are there? There are a total of 'm+n' a's.

\rightarrow a^{m}\times a^{n}=a^{m+n}

Annabelle added the power and Navene multiplied the power. So, Annabelle is correct.

Learn more.

Product rule a^m\times a^n=a^{m+n}

Division rule a^{m}\div a^{n}=a^{m-n}

Power rule (a^m)^{n}=a^{mn}

Power rule a^{m^{n}}=a^{(m^{n})}

Root rule \sqrt[m]{a} =a^{\frac{1}{m} }

→ For even power root, the base should be non-negative.

Zero power rule a^{0}=1\;(a\neq 0)

Negative power rule \dfrac{1}{a^m} =a^{-m}\;(a\neq 0)

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