Question

Pls help


In This question

Answer 1

Explanation:

Answer :

\rule{100}2

Given :

In a rectangle,

Length = 2 cm + width

Perimeter = 48

To Find :

Area of the given rectangle

Solution :

Let width of the rectangle be ' x '

So, it's length will be ' x + 2 '

We know that,

\sf Perimeter\:of\:Rectangle=2(length+breadth)PerimeterofRectangle=2(length+breadth)

\sf 48 = 2 ( x + x + 2 )48=2(x+x+2)

\sf\implies 48 = 2 ( 2x + 2 )⟹48=2(2x+2)

\sf\implies 48 = 4x + 4⟹48=4x+4

\sf\implies 48 - 4 = 4x⟹48−4=4x

\sf\implies 44 = 4x⟹44=4x

\sf\implies x =\dfrac{44}{4}⟹x=

4

44

\sf\therefore x = 11∴x=11

Hence,

width of the rectangle = 11 cm.

Length => 2 + 11 = 13

Now,

\sf Area\: of\: Rectangle = length\times breadthAreaofRectangle=length×breadth

Substitute the given values. we get,

= 11 × 13

= 143 cm²

Therefore, Area of the given rectangle is 143 cm²

\rule{200}2