Math, asked by Royal31, 1 year ago

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Answered by Anonymous
1
=(1+tan²A) +(1+(1/tan²A))

[USING sec²A=1+tan²A]

=sec²A+(1+cot²A)

[USING cosec²=1+cot²A]

=sec²A+cosec²A

=(1/cos²A) +(1/sin²A)

=(sin²A+cos²A)/sin²Acos²A

[USING sin²A+cos²A=1]

=1/[sin²A(1-sin²A)]

=1/(sin²A-sin^4A]

So option A is the right answer.
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