Question

[Ans. 2ms3-0.4 ms --]
4. A car travelling at a velocity of 10 ms -1 due north speeds up uniformly to a velocity of
25 ms-1 in 5 s. Calculate the acceleration during this period.
[Ans. 3 ms-2)
​

Answer 1

Given :

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 25 m/s
• Time (t) = 5 seconds

To find :

• Acceleration (a)

According to the question,

In this question we will use Newton's first equation of motion,

→ v = u + at

Where,

• v stands for Final velocity
• u stands for Initial velocity
• t stands for Time
• a stands for Acceleration

→ Substituting the values,

→ 25 = 10 + a × 5

→ 25 - 10 = 5a

→ 15 = 5a

→ 15 ÷ 5 = a

→ 3 = a

.°. The acceleration is 3 m/s²...

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Answer 2

Given :-

☄ Initial velocity, u = 10 m/s

☄ Final velocity, v = 25 m/s

☄ Time, t = 5 sec

To find :-

Acceleration during the period

Solution :-

using equation of motion .i.e.,

➠ v = u + at

➠ 25 = 10 + (a)(5)

➠ 25 - 10 = 5a

➠ 15 = 5a

➠ a = 15/5

➠ a = 3m/s²

thus, the acceleration is 3 m/s²

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