Question

Ans. 3150 joule.
4. Calculate the amount of heat required to raise the temperature of 20
gm. of water from 30°C. to 80°C.​

Answer 1

Explanation:

Specific capacity of water(s) = 4.2 J/g°C

Mass(m) = 20 gm

Temperature change(dT) = 80°C - 30°C = 50°C

Heat required = msdT = 20 × 4.2 × 50 J

= 4200 J = 4.2 KJ