Question

Ans fast plzz....

A person travelling at 43.2 km/h applies the brake giving a deceleration of 6.0 m/s² to his scooter. How far will it travel before stopping?

Answer 1

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤

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Initial velocity=u=43.2km/hr =43.2 x 5/18 =12 m/s
final velocity =V=0m/s [ As brakes are applied]
Acceleration=a= -6.0m/s2
Distance =s=?

Formula to be used : v²-u²=2as

s= v²-u²/2a
s=0²-12²/2x-6
S=12m

Hence distance travelled before stopping is 12m

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HOPE IT HELPS U.
#BE BRAINLY.

Answer 2

u = 43.2 km/h = 43.2 X 5/18 = 12 m/s
v = 0 m/s ( as vehicle comes to stop finally )
a = -6 m/s²
Using v²-u² = 2as
(0)²-(12)² = 2 X (-6) X s
0-144 = -12s
-144 = -12s
s = -144/-12 = 12m
s = 12m