☺☺Ans for Q16. THANKS!!!!!☺☺☺☺☺
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the first term=56
the last term=497 difference = 7
Tn=a+(n-1)d
497=56+(n-1)7
497-56=(n-1)7
441/7=n-1
63+1 =n
n=64
so,there are 64 terms divisible
sum=n/2[a+l]
=64/2(56+497)
=17696
the last term=497 difference = 7
Tn=a+(n-1)d
497=56+(n-1)7
497-56=(n-1)7
441/7=n-1
63+1 =n
n=64
so,there are 64 terms divisible
sum=n/2[a+l]
=64/2(56+497)
=17696
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