Question

ans is -125 but how​

Answer 1

3 aur 21 cross cancel hoke denominator me 7 bachega

Aur 8 aur 16 cross cancel hoke numerator me 2 bachega

Thus wo ho jayga

(2/7)^-5 =(2/7)^x

That means

x=-5

x³=(-5)³

=-125