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Noreen1256:
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f=880×10^3Hz P=10×10^3W this means that the radio transmitter uses 10×10^3 joules of energy per second using planck 's equation E=hf(for energy of single photon) E=nhf (for n photons) 10×10^3=n×6.625×10^-34×880×10^3 n=10×10^3/6.625×10^-34×880×10^3 n=1.71×10^31 thus b is the correct option
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One KW is the power or energy per unit time.
1000 J/s is the power.
We know that, E=HV. Where E=energy of a single photon, H = Planck ‘s constant and V=frequency of the photon.
Now simply equate as power = energy/sec.
Suppose nphotons are emitted per second, then we can say-
Power=nHV
n=Power/HV.
Solve it for the answer.
Hope that helped
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