Math, asked by parvrajjain27p7hszu, 11 months ago

ans me fast tommorow is my board exam

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Answered by sraddhavaranasi22

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Answered by mukulbhati144

x2-(2b-1)x + (b2-b-20) = 0

x2-2bx+1× +b2-b-20=0

x2-2bx+1-20+b2-b=0

x2-2bx-19+b2-b=0

x2=0+2bx+19-b2+b

$\sqrt{2bx + 19 - {b + b}^{2} }$

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ans me fast tommorow is my board exam