Question

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Answer 1

Answer:

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Step-by-step explanation:

(i) According to the question,

F = (9/5)C + 32

Solving the equation,

We get,  When C = 0, F = 32

When C = -10 , F = 14

The points to be plotted are (0, 32), (-10, 14)

(ii) When C = 30,  F = (9/5)C +32

F = (9×30)/5+32

= (9×6)+32

= 54+32

= 86oF

(iii) When F = 95,

95 = (9/5)C +32  

(9/5)C = 95-32

(9/5)C =63

C = (63×5)/9  

=35oC

(iv) When C = 0,

F = (9/5)C +32

F = (9×0)/5 +32

=0+32

=32oF

When F = 0,

0 = (9/5)C+32

(9/5)C = 0-32

(9/5)C = -32

C = (-32×5)/9

=-17.7777

=-17.8oC

(v) When F = C,

C = (9/5)C+32

C – (9/5)C = 32

(5-9)C/5 =32

(-4/5)C = 32

(-4/5)C = (-32×5)/4

= – 40oC

Hence, -40o is the temperature which is numerically the same in both Fahrenheit and Celsius.