Question

ans my question quickly plz plz​

Answer 1

Step-by-step explanation:

molecular maas of AgCl=143.362g/mol

If 143.362 g of AgCl containns 35.5g chlorine

then amount of chlorine in .574g= .574×35.5×1/143.362

=.142g

percentage of chlorine in given compound=.142×100 ×1/.378

=37.56 percent

hope it helps you dude

Answer 2

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