Question

Ans of question 6th......

Answer 1

We want to find the maximum value of y

For the maximum value of y we have to take the value of x by which the denominator is less than numerator

Then, x-5

On taking x = 5

then,

$y = \frac{50}{ [{ {(x - 5)}^{2} + 5] }^{2} } \\ \\ = > y = \frac{50}{[ { {(5 - 5)}^{2} + 5] }^{2} } \\ \\ = > y = \frac{50}{25} = 2$

So, the maximum value of y will be 2