find the value of x
please explain it
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Answer:
x/y=a+2/a-2
x=(a+2/a-2)y in (x^2-y^2/x^2+y^2)
=>[(a+2/a-2)y]^2-y^2/[(a+2/a-2)y]^2+y^2
=>by solving these you get
(a+2)^2(y^2)-(a-2)^2(y^2)/(a+2)^2(y^2)+(a-2)^2(y^2)
Take y^2 common in numerator and denominator and cancel them.
Then you get the following when you simplify
=>a^2+4a+4-a^2+4a-4/a^2+4a+4+a^2-4a+4
=>8a/2a^2+8
=>4a/a^2+4
Hope my answer is useful.
mithlesh87:
not satisfied
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