Question

ans please 13 question ​

Answer 1

Hii its tom85

differentiating with respect to X we get

dy/dx= (1 - sinx)/cosx{ (- sinx +sin^2x + cos^2x)/(1-sonx)^2}

dy/dx = (1 -sin x)^2/(1 - sinx)^2 cosx

dy/dx = sec x

explanation

differentiation of

log (f(x)) = f'(x)/f(x)

sinx = cosx

cosx = - sinx

d(u/v)/dx = ( vdu/dx - udv/dx)/v^2

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hope it may helps you dude

Answer 2

Answer:

hey mate first use d/dx(log x)

again use u/v rule

as u know sin^2x+cos^2x=1

and 1/cosx=secx

option D

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