ans plzzz fast. find the height of the tower, ans step by step
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let ABC be the tower and D be the distance moved towards the tower.
angle ABC= 45 degree
angle ADC= 60 degree
CD = 40m
let height of the tpwer be h metre and BD = x metre
from triangle ABC
tan 45 degree = P/B
1 = h/40+x
h = 40+x equation 1
from triangle ABD
tan 60 degree = P/B
root 3= h/ x
h= root3x equation 2
from 1 and 2
40+x=root 3x
40 =root3x-x
40 = x(root3-1)
x= 40/root3-1
put value of root 3= 1.732
x = 40/ 1.732-1
x= 40/0.732
x= 54.64m
put the value of x in equation number 1
h= 40 + x
h = 40 + 54.64
h = 94.64 m (approximately)
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hey...your answer is in the attachment
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