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x=√7-√5,y=√5-√3,z=√3-√7
Then we have to find x^3+y^3+z^3-2xyz
If we add x,y and z we get
x+y+z=√7-√7+√5-√5+√3-√3=0
If x+y+z=0=>x^3+y^3+z^3=3xyz
So,we get 3xyz-2xyz=xyz=(√7-√5)(√5-√3)(√3-√5)=√105-7√5-5√3-3√7+7√3+5√7+3√5-√105
=2√3+2√7-4√5
=2(√3+√7-2√5)
Hope it helps
Then we have to find x^3+y^3+z^3-2xyz
If we add x,y and z we get
x+y+z=√7-√7+√5-√5+√3-√3=0
If x+y+z=0=>x^3+y^3+z^3=3xyz
So,we get 3xyz-2xyz=xyz=(√7-√5)(√5-√3)(√3-√5)=√105-7√5-5√3-3√7+7√3+5√7+3√5-√105
=2√3+2√7-4√5
=2(√3+√7-2√5)
Hope it helps
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