Question

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Answer 1

Answer:

Ques no.1 a) False       b)  True

Ques no.2- a) 10_002

Sum of the digits- 3

So, the sum of the number should be divisible by 9 . So, 9 is the smallest number after 3 which is divisible by 9

So, the smallest number- 9-3= 6

= 106002

Ans. The missing number is 6.

b) 42036 is divisible by 6

2x3= 6

So, the number should be divisible by both 2 and 3.

42036 is divisible by 2 because it ends with 6 , which is a multiple of six

Sum of the number= 15 , which is divisible by 3

Ans. The number 42036 is divisible by 6 because it is divisible by both 2 and 3.

c) Sol- 2nd multiple of 11=

11x1= 11

11x2=22

4th multiple of 12= 12x1=12 , 12x2=24 , 12x3= 36 , 12x4= 48

Product of  2nd multiple of 11 and 4th multiple of 12= 22x48= 1056

Ans. The product is 1056

d) Yes, two numbers can have 40 as their HCF and 20 as a LCM because hcf of the number must be a factor of the LCM .

Since, 20 is a factor of 40, it is possible.

e) Prime factorization of the numbers:

306 = 2 × 3 × 3 × 17

360 = 2 × 2 × 2 × 3 × 3 × 5

63 = 3 × 3 × 7

LCM(306, 360, 63)

= 2 × 2 × 2 × 3 × 3 × 5 × 7 × 17

= 42840

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Answer 2

1. 106002

(sum of no.s is divisible by 9)

2. yes (its divisible by 2 and 3 so it's divisible by

6 too)

3. 1056

(2nd multiple of 11=22

4th multiple of 12=48

22x48=1056)

4. No because HCF is always smaller than the LCM.

5. LCM=42840

HCF=3

6. 16

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