Question

ans this fast wih steps ​

Answer 1

Point on x-axis is given as O(x, 0)

A(-3,4) and B(1,-4)

Let, OA = OB

Now apply distance formula.

$\sqrt{(x - ( - 3)) {}^{2} + (0 - 4) {}^{2} } = \sqrt{(x - 1) {}^{2} +(0 - ( - 4)) {}^{2} }$

$\sqrt{(x + 3) {}^{2} + 16} = \sqrt{(x - 1) {}^{2} + 16 }$

Now on squaring both side.

$(x + 3) {}^{2} + 16 = (x - 1) {}^{2} + 16$

${x {} }^{2} + 6x + 9 = x {}^{2} - 2x + 1$

$8x = - 8$

$x = - 8 \div 8$

$x = - 1$

Hence point is O(-1,0).

THANKS

Answer 2

Answer:

Step-by-step explanation:

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