Science, asked by lisharaj043p3xl5p, 1 year ago

ans this q in a proper manner so that i can understand properly

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lisharaj043p3xl5p: hey in hurry i asked this q in sc sub so plzz dont mind:(

Answers

Answered by Racheet

at first the width can be found by 2 methods
1)BC-FG÷2
2)DC-HG÷2
IN both cases the width is 4cm
Now trapizium HGDC AREA FORMULAE is 1/2×h×(sum of parallel sides)
thus
1/2×4×(20+28)
=1/2×4×48=96
now area of HGDC=ABFE
Now trapizium BFGC has area
1/2×4×(24+32)
=1/2×4×56=212
now area of BFGC=AEHD

hope it helps you
plz mark it as most brainliest answer

lisharaj043p3xl5p: thank u so much

lisharaj043p3xl5p: but why u divided it by 2

lisharaj043p3xl5p: and ur ans is wrong

lisharaj043p3xl5p: correct ans is 112

Racheet: oh sorry 56×2=112

Racheet: i divided it by 2 because there are 2 distances left when subtracting FG from BC but we need only one for our sum

Racheet: and that was just a multiplication mistake

Racheet: but still sorry

lisharaj043p3xl5p: its ok:)

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