Question

ANSER IT AND ALSO DRAW FIGURE. BEST ANSWER WILL BE MARKED AS BRAINLIEST

Answer 1

Answer:

Step-by-step explanation:

Let the circle touches the sides  AB,BC and CA of triangle ABC at D, E and F 

Since lengths of tangents drawn from an external point are equal  We have

 AD=AF,  BD=BE  and CE=CF

Similarly EB=BD=r

Then we have  c = AF+FC

                   ⇒ c = AD+CE

                   ⇒ c = (AB-DB)(CB-EB)

                   ⇒ c = a-r +b-r

                   ⇒ 2r =a+b-c

                        r =( a+b-c)/2

Answer 2

Answer:

Step-by-step explanation:

Here's your answer with proper solution. I hope this will help you....