Anser the question 16 without process and 17 with process... please....
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16.
Note: A number is divisible by 6. if it is divisible by 2 and 3.
(1) 17852.
= > 17852 is divisible by 2. Since the units place is 2.
= > 17852 is not divisible by 3.Since the sum of digits of 1 + 7 + 8 + 5 + 2 = 23 which is not divisible by 3.
Therefore 17852 is divisible by 2, not 3.
Hence, 17852 is not divisible by 6.
(2) 639210
= > 639210 is divisible by 2. Since the units place is 0.
= > 639210 is divisible by 3. Since the sum of digits 6 + 3 + 9 + 2 + 1 + 0 = 21 which is divisible by 3.
Therefore 639210 is divisible by 2 and 3.
Hence, 639210 is divisible by 6.
17.
Prime factorization of 72 = 2 * 2 * 2 * 3 * 3
Prime factorization of 120 = 2 * 2 * 2 * 3 * 5
Prime factorization of 192 = 2 * 2 * 2 * 2 * 2 * 2 * 3
HCF(72,120,192) = 2 * 2 * 2 * 3
= 24.
Hope this helps!
Note: A number is divisible by 6. if it is divisible by 2 and 3.
(1) 17852.
= > 17852 is divisible by 2. Since the units place is 2.
= > 17852 is not divisible by 3.Since the sum of digits of 1 + 7 + 8 + 5 + 2 = 23 which is not divisible by 3.
Therefore 17852 is divisible by 2, not 3.
Hence, 17852 is not divisible by 6.
(2) 639210
= > 639210 is divisible by 2. Since the units place is 0.
= > 639210 is divisible by 3. Since the sum of digits 6 + 3 + 9 + 2 + 1 + 0 = 21 which is divisible by 3.
Therefore 639210 is divisible by 2 and 3.
Hence, 639210 is divisible by 6.
17.
Prime factorization of 72 = 2 * 2 * 2 * 3 * 3
Prime factorization of 120 = 2 * 2 * 2 * 3 * 5
Prime factorization of 192 = 2 * 2 * 2 * 2 * 2 * 2 * 3
HCF(72,120,192) = 2 * 2 * 2 * 3
= 24.
Hope this helps!
siddhartharao77:
:-)
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