Anshul bought two radio sets for Rs 500. He sold one at a loss of 12% and the other at a gain of 8%. He neither gained or lost in his whole transaction. find the cost price of each radio.
Please do it fast and your solution should be in details.Thank you
Answers
Answer:
Rs.200 and Rs.300
Step-by-step explanation:
1) Let the cost price of one radio be Rs. x
Let the cost price of another radio be Rs. y
Total cost price of two radios = Rs. 500
x + y = 500
y = 500 - x ---eq(1)
2) CP of one radio = Rs. x
Loss % on one radio = 12%
SP = CP * (100 - Loss%)/100
= x * (100 - 12)/100
= x * 88/100
= x * 0.88
= 0.88x
3) CP of the another radio = Rs. y
Gain % on goat= 8%
SP = CP * (100 + Gain %)/100
= y * (100 + 8)/100
= y * 108/100
= y * 1.08
= 1.08y
4) Total CP of two radios Rs.5000
Total SP of two radios = 0.88x + 1.08y
Given : On whole transaction he gained neither nor he lost
That means SP = CP
0.88x + 1.08y = 500
0.88x = 500 - 1.08y
0.88x + 1.08(500 - x) = 500 (From eq(1))
0.88x + 540 - 1.08x = 500
-0.2x + 540 = 500
540 - 500 = 0.2x
0.2x = 40
x = 40/0.2
x = 400/2
x = 200
Therefore Cost Price of one radio = x = Rs.200
Cost Price of another radio = y = 500 - x = 500 - 200 = Rs. 300
Answer:
your answer is ₹200 and ₹300