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★ LOGARITHMIC REDUCTIONS ★
Given that ;
☣ ( x√x ) ^x = ( x )^ x√x
By reducing the equivalents by taking logarithms on both the side -
☣ ( x√x ) ^x = ( x ) ^ x√x
☣ log ( x√x ) ^x = log ( x^x√x)
☣ x log ( x√x ) = x√x log ( x )
☣ x log ( x^3/2) = x√x log ( x )
☣ 3x/2 log ( x ) = x√x log ( x )
☣ 3x log ( x ) = 2x√x log ( x )
☣ 2x√x log ( x ) - 3x log ( x ) = 0
☣ x log ( x ) [ 2√x - 3 ] = 0
for the above relationship to be satisfied ,
either , x = 0 , log ( x ) = 0 , 2√x - 3 = 0
x ≠ 0 , because 0⁰ is indeterminate format
aslike , x log ( x ) = log ( x )^x , and violating logarithmic domain too
☣ log ( x ) = 0 , for sure x = 1
and if 2√x - 3 = 0 , then for sure , x = 9/4
Hence , the possible real numbers are x = 1 , 9/4
Option B is correct for above all results
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Given that ;
☣ ( x√x ) ^x = ( x )^ x√x
By reducing the equivalents by taking logarithms on both the side -
☣ ( x√x ) ^x = ( x ) ^ x√x
☣ log ( x√x ) ^x = log ( x^x√x)
☣ x log ( x√x ) = x√x log ( x )
☣ x log ( x^3/2) = x√x log ( x )
☣ 3x/2 log ( x ) = x√x log ( x )
☣ 3x log ( x ) = 2x√x log ( x )
☣ 2x√x log ( x ) - 3x log ( x ) = 0
☣ x log ( x ) [ 2√x - 3 ] = 0
for the above relationship to be satisfied ,
either , x = 0 , log ( x ) = 0 , 2√x - 3 = 0
x ≠ 0 , because 0⁰ is indeterminate format
aslike , x log ( x ) = log ( x )^x , and violating logarithmic domain too
☣ log ( x ) = 0 , for sure x = 1
and if 2√x - 3 = 0 , then for sure , x = 9/4
Hence , the possible real numbers are x = 1 , 9/4
Option B is correct for above all results
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Anonymous:
perfect
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