Answer 5 question .
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Coordinate of P is P (2,0).
Step-by-step explanation:
Coordinate of points on x axis is of the form (x,0).
Now,by section formula coordinate of mid point
= (x1 + x2)/2 , (y1 +y2)/2.
P(x, 0) = -2 +6/2 , 0 +0/2
x, 0 = 4/2 , 0
x = 2.
Hence point P (2, 0 ) is equidistant from A(-2,0) and B(6,0)
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