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I'll solve it tomorrow dear... okay ?
i know it ...bt im sleeping now
btw its from ionic equilibrium na ?
ohh okay...gn take care dear
sweet dreams
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In titration, M1V1 = M2V2
where, M1 = concentration of acid (here, HCI),
V1 = volume of acid ,
M2 = concentration of solution (KOH) and,
V2 = volume of KOH solution...
given, M1 = 1.0M , V1 = 7.5cm^3 and , V2 = 50cm^3
so, M2 = (M1V1)/V2 = 1×7.5/50
=> M2 = 0.15M
hence , the concentration of KOH solution is 0.15M ....
where, M1 = concentration of acid (here, HCI),
V1 = volume of acid ,
M2 = concentration of solution (KOH) and,
V2 = volume of KOH solution...
given, M1 = 1.0M , V1 = 7.5cm^3 and , V2 = 50cm^3
so, M2 = (M1V1)/V2 = 1×7.5/50
=> M2 = 0.15M
hence , the concentration of KOH solution is 0.15M ....
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